This is our “Enhanced” course on the 2020 National Electrical Code® for Electrical Exam Preparation. While this course has all the same material as our famous Fast Trax® Black it does differ in that it doesn’t offer the same level of personal attention and support as our flagship courses. However, this PLUS upgrade offers 12-month access to FastTraxTube.com – See the NOTICE below.
Here is what WILL or WILL NOT be included in this course:
1) The student in the “Enhanced” course WILL have access to the 100 question and 750 electrical question database*. While we may include quizzes at the end of various units, this is not the same level of interaction as our Fast Trax® Black.
2) The student in the “Enhanced” course WILL have access to www.FastTraxTube.com for 12 Months.
CHECK YOUR STATE BEFORE YOU BUY ANY COURSE TO SEE WHAT NEC THEY ARE ON – CHECK HERE
Log In Requirements – You do not need to wait for login instructions. Simply login and visit your profile for your course list.
Fast Trax® Budget – log in through www.fasttraxsystem.com
* The 750 Question Database was added 7/21/2023 and may only be available for a limited time.
NOTICE: With this PLUS Upgrade you also get 12 months of Access to FastTraxTube.com as well. Simply go to www.FastTraxTube.com and create a FREE PLAN and then email us a copy of our invoice (from this course purchase) and include your new Username and Email you signed up with on FastTraxTube.com and your Free Plan will be upgraded to the Annual Membership.
DEMO
Course Features
- Lectures 23
- Quiz 1
- Duration Lifetime access
- Skill level Intermediate
- Language English
- Students 248
- Certificate Yes
- Assessments Self
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4 Comments
in problem 4 of unit 11 competency test we have a disposer rated at 1/3 HP. at 115 volts . 1/3 HP is equivalent to 245 watts. or 245 VA.The answer sheet says the disposer is 828 VA. It gets 828 by multiplying 115 volts x 7.2 amps. i don’t understand where the 7.2 amps came from. The amperage should be 245 Watts / 115 volts = 2.13 amps. Would you please explain? Thank you Robert Z.
Robert,
As stated in our live Wednesday night sessions, the garbage disposer is in HP and its a motor. You use the FLC (Full Load Current) of a motor from Tables 430.247, 430.248, 430.249, or 430.250. Once you have the FLC you would multiple the FLC by the voltage to get the Volt-Amperes value to be used in the calculation.
I encountered a question: What is the demand factor for a school with an area of 100,000 sq ft, given that the load before applying the demand factor is 2.5 MVA? Can you please help.
Greetings- You really should consider using the built in “Fast Trax Interact” feature so others in the same course you are in learn as well.
As stated, you would first establish the load per square feet. So, 2.5 MVA/100,000 = 25 VA per sq. Ft.
Then go to the table.
First 3VA at 100%= 3 VA ft²
Next 17VA at 75% = 12.75 VA ft²
Remaining 5VA at 25% = 1.25 VA ft²
Total is 17 VA ft²
Lastly 17 VA ft² x 100,000 ft² = 1,700,000 VA = 1.7 MVA
FYI- This is the same example in LINK under 220.86 if you want to review it.